Stupid math question

[Hatman]

A line is perpendicular to the line (x/3) + (y/4) = 1 and passes through the point (4,1).

Find the equation of the line.

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Well, for me I think its simply (x/3)+1 and (y/4)+1 but really arent sure.

Thanks 4 help. Due to being a computer site some guys will be good with math

 

[WC Annihilus]

What I would do is get y by itself, cause then you'll know the slope. Then you just do inverse reciprocal for the slope of the new line, and use the point-slope form

 

[Hyper]

Another stupid question...

Why do some people say Math and others say Maths

I know I say Maths.

 

[macgamesrule]

(x/3) + (y/4) = 1 and passes through the point (4,1)

4/3*x+y = 4

y = -4/3*x + 4

New line:

y = 3/4*x + b (perpendicular is inverse reciprocal slope as WC said)

1 = 3/4*4 + b

b = 1 - 3 = -2

y = 3/4*x - 2

 

[WC Annihilus]

Mac, you flipped the x and y when solving

 

[macgamesrule]

Yea figured I would... that's what happens when I'm in a rush. Usually I check such things in Mathcad etc but I was on my way out the door...

edited btw

 

[Rastalovich]

Best way of thinking about an equation for a line that passes through a known point (a,b), is that you now know that at that point, when x=a y=b. You can put that back into the equation to find out what you want from it.